Answer:
Energy of a single photon with the given wavelength is \(E=3.32\times 10^{-19}\ J\)
Explanation:
It is given that,
The wavelength of yellow light, \(\lambda=6\times 10^{-7}\ m\)
The equation that gives the relationship between the energy and the frequency of the wave is called Plank's equation. Mathematically, it can be written as :
\(E=h
u\)
where \(u\) is the frequency of the wave and \(u=\dfrac{c}{\lambda}\)
h is Planck's constant
So, \(E=\dfrac{hc}{\lambda}\)
\(E=\dfrac{6.62\times 10^{-34}\ J-s\times 3\times 10^8\ m/s}{6\times 10^{-7}\ m}\)
\(E=3.32\times 10^{-19}\ J\)
So, the energy of photon is \(E=3.32\times 10^{-19}\ J\)
