A)
Earlier, The length of the angelfish = \(1 \frac{1}{2}\) inches
Now, the length of angelfish = \(2 \frac{1}{3}\) inches
We have to determine the grown length of angelfish
= \(2 \frac{1}{3}\) - \(1 \frac{1}{2}\)
= \(\frac{7}{3}- \frac{3}{2}\)
LCM of '2' and '3' is '6',
= \(\frac{14-9}{6}\)
= \(\frac{5}{6}\) inch
Therefore, the angelfish has grown by \(\frac{5}{6}\) inch.
B)
We have to determine the increased length of angelfish in feet.
Since \(1 inch = \frac{1}{12}\) foot
So, \(\frac{5}{6} inch = \frac{5}{6} \times \frac{1}{12} = \frac{5}{72}\)
= 0.069 foot.
