we know that
The function to find the volume of air inside a basketball is equal to find the volume of a sphere
\(V(x)=\frac{4}{3} \pi x^{3}\)
where
the variable x is the radius of the basketball
so
For \(x=r\)
\(V(r)=\frac{4}{3} \pi r^{3}\)
V(r) represent the volume of the basketball when the radius is r
therefore
the answer is the option B
the volume of the basketball when the radius is r
