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The force F of attraction between two bodies varies jointly as the weights of the two bodies and inversely as the square of the distance between them. Express this fact as a variation using c as a constant. Use M1 and M2 for the weights of the two bodies.

Verified Answer :

Answer:

I think the answer is \(c=F(d^2)/(m_1m_2)\)

Step-by-step explanation:

REMEMBER: The formula for joint variation is:

\(c=y/xz\) OR \(y=cxz\).

Substitute:

\(F=Km_1m_2/d^2\)

then change to:

k= constant, they want you to use "c" instead:

\(c=F(d^2)/(m_1m_2)\)

Hope this helps!

aksnkj

The expression of force of attraction F will be \(F=c\dfrac{M_1M_2}{d^2}\).

Given information:

The force F of attraction between two bodies varies jointly as the weights of the two bodies and inversely as the square of the distance between them.

\(M_1\) and \(M_2\)  are the weights of the two bodies.

Let d be the distance between the two bodies.

The force follows inverse square law.

The expression of force can be written as,

\(F\propto \dfrac{M_1M_2}{d^2}\\F=c\dfrac{M_1M_2}{d^2}\)

where c is the proportionality constant.

Therefore, the expression of force of attraction F will be \(F=c\dfrac{M_1M_2}{d^2}\).

For more details, refer to the link:

https://brainly.com/question/9510464

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