Answer:
3.6 units
Step-by-step explanation:
Given: The two points that are P(5,1) and Q(3,4).
To find: The distance between these two points.
Solution: It is given that there are two points that are P(5,1) and Q(3,4).
The distance between these two points can be found out as using the distance formula that is:
\(PQ=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2 }\)
\(PQ=\sqrt{(4-1)^2+(3-5)^2}\)
\(PQ=\sqrt{(3)^2+(-2)^2}\)
\(PQ=\sqrt{9+4}\)
\(PQ=\sqrt{13}\)
\(PQ=3.6 units\)
Thus, the distance between the given two points is 3.6 units.
