What is the change in enthalpy when 250 g of water vapor condenses at 100oC? (ΔHv = 40.67 kJ/mol)
Answer:-564.4996 kJ is the change in enthalpy when 250 g of water vapor condenses at 100°C.
Explanation:
\(H_2O(l)\rightarrow H_2O(g),\Delta H_v=40.67 kJ/mol\)
\([tex]H_2O(g)\rightarrow H_2O(l),\Delta H_c=-40.67 kJ/mol\)
Moles of water = \(\frac{250 g}{18 g/mol}=13.88 mol\)
Heat of condensation of 1 mol of water = \(\Delta H_v=-40.67 kJ/mol\)
Heat change when 250 grams of water condenses at 100° C:
\(-40.67 kJ/mol\times 13.88 mol=-564.4996 kJ\)
-564.4996 kJ is the change in enthalpy when 250 g of water vapor condenses at 100°C.