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What is the value of h when the function is converted to vertex form?


Note: Vertex form is

f(x)=a(x−h)2+k


f(x)=x^2+10x+35

Verified Answer :

I hope this helps you


f (x)=x^2+10x+25+10


f (x)=(x+5)^2+10


h= -5


k=10

abidemiokin

The value of h when the function is converted to vertex forms is -5

Vertex form of an equation

The standard form of an equation is expressed as:

f(x)=a(x−h)2+k

Given the quadratic equation f(x)=x^2+10x+35

Using the completing the square method

f(x)=x^2+10x+35

f(x)=(x^2+10x + 5^2)-5^2+35
f(x) = (x+5)^2 - 25 + 35

f(x) = (x+5)^2 + 10

Compare

h = -5

Hence the value of h when the function is converted to vertex forms is -5

Learn more on vertex form here: https://brainly.com/question/525947

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