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Verified Answer :

LammettHash

The work is equivalent to the dot product of the two vectors.

\(W=\mathbf F\cdot\mathbf r=\langle2,-1,-1\rangle\cdot\langle3,2,-5\rangle=6-2+5=9\)

zohazoee

Answer:

\(W=9\)

Step-by-step explanation:

applying the following formula

\(W=r.f\)

here the dot indicates the dot product

then

\(W=(3i+2j-5k).(2i-j-k)\)

taking dot product

\(W=3.2+2.(-1)+(-5).(-1)\)

\(W=6-2+5\)

\(W=9\)

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