A disco ball is shaped like a sphere with a diameter of 16 inches to the nearest square inch what is the surface area of the disco ball
the surface area of a sphere:
A = 4 pi r^2
where pi = 3.1416
r is the radius
since diameter is given
r = d / 2
r = 16 / 2
r = 8
A = 4 pi (8^2)
A = 804 sq in is the surface area of the disco ball
By using the general formula for the surface area of a sphere, we will see that the surface area of the disco ball is 804 in^2
We know that for a sphere of radius R the surface is:
S = 4πR^2
where π = 3.14
In this case, we know that the diameter is 16 inches, and the diameter is twice the radius, then we have:
R = (16 in)/2 = 8in
Replacing that in the surface equation we get:
S = 43.14(8 in)^2 = 803.84 in^2
Rounding to the nearest square inch, we get:
S = 804 in^2
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