at 120.0 c the pressure of a sample of nitrogen is 1.07 atm. what will the pressure be at 205 c assuming constant volume?
We can use the ideal gas
equation which is expressed as PV = nRT. At a constant volume and number of
moles of the gas the ratio of T and P is equal to some constant. At
another set of condition, the constant is still the same. Calculations are as
follows:
T1/P1 = T2/P2
P2 = T2 x P1 / T1
P2 = 393.15 K x 1.04 atm / 478.15 K
P2 = 0.86 atm
Answer:
1.30 atm (rounded)
Explanation:
P1= 1.07 atm
P2= ?
T1= 122 Celsius (+273 to convert to Kelvin)= 395 K
T2= 205 Celsius (+273 to convert to Kelvin)= 478 K
\(\frac{P1}{T1} = \frac{P2}{T2}\)
\(\frac{1.07 atm}{395 K} =\frac{P2}{478 K}\)
\(P2=\frac{(1.07 atm) (478 K)}{395 K}\)
\(=\frac{511.46}{395} = 1.29483544304\)
= 1.30 atm