Answer:
\(15.5\ m^{2}\)
Step-by-step explanation:
we know that
The area of the figure is equal to the area of a rectangle plus the area of semicircle
Step 1
Find the area of the rectangle
The area of the rectangle is equal to
\(A=bh\)
we have
\(b=6\ m\)
\(h=2\ m\)
substitute
\(A=6*2=12\ m^{2}\)
Step 2
Find the area of semicircle
The area of semicircle is equal to
\(A=\frac{1}{2}\pi r^{2}\)
we have
\(r=3/2=1.5\ m\)
substitute
\(A=\frac{1}{2}(3.14)(1.5^{2})=3.5\ m^{2}\)
Step 3
Find the area of the figure
\(12\ m^{2}+3.5\ m^{2}=15.5\ m^{2}\)
