Answer:
The correct answer is option A.
Explanation:
The Planck's constant is defines ratio of an energy of quantum of an electromagnetic radiation to frequency of the electromagnetic radiation.The units of the constant is J.s (Joule seconds).
The Planck's equation is given as
\(E=h
u=\frac{h\times c}{\lambda}\)
where,
E = energy of photon = ?
h = Planck's constant = \(6.63\times 10^{-34}Js\)
c = speed of light = \(3\times 10^8m/s\)
\(1 J=6.242\times 10^{18} eV\)
\(h = 6.63\times 10^{-34}Js=6.63\times 10^{-34}\times 6.242\times 10^{18} eV.s\)
\(=4.138\times 10^{-15} eV.s\approx 4.14\times 10^{-15} eV.s\)
Hence, the correct answer is option A.
