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\(( \frac{r}{s} )(6)= \frac{r(6)}{s(6)}\)

r(6)=3(6)-1=18-1=17
s(6)=2(6)+1=12+1=13
\(( \frac{r}{s} )(6)= \frac{r(6)}{s(6)}= \frac{17}{13}\)

Answer:

\(\frac{r}{s}(6)=\frac{17}{13}\)

Step-by-step explanation:

Given : \(r(x)=3x-1\)

           \(s(x)=2x+1\)

To Find: (r/s)(6)

Solution:

\(r(x)=3x-1\)

\(s(x)=2x+1\)

So, \(\frac{r}{s}(x)=\frac{3x-1}{2x+1}\)

Substitute x =6

So, \(\frac{r}{s}(6)=\frac{3(6)-1}{2(6)+1}\)

\(\frac{r}{s}(6)=\frac{17}{13}\)

Hence \(\frac{r}{s}(6)=\frac{17}{13}\)

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