The equation for the circle is:
x2+y2−12x+6y−19=0
What is the center of the circle?
A(-6, 3)
B(12, -6)
C(6, -3)
D(-12, 6)
x2+y2−12x+6y−19=0
What is the center of the circle?
A(-6, 3)
B(12, -6)
C(6, -3)
D(-12, 6)