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A rectangle’s length is 5 inches more than twice its width. Its area is 50 square inches. Which equation can be used to find its width, w? 2w(2w + 5) = 50 2w(w + 5) = 50 w(2w + 5) = 50 w(w + 5) = 50

Verified Answer :

carlosego

For this case we define the following variables:

  • L: length of the rectangle
  • w: width of the rectangle

We have that by definition, the area of a rectangle is given by:


\(A = w * L\)

Then, we have that the length is 5 inches more than twice its width:

\(L = 2w + 5\)

Substituting values we have:

\(w (2w + 5) = 50\)

Answer:

An equation that can be used to find its width, w is:

\(w (2w + 5) = 50\)

The equation that can be used to find the width of the rectangle is \(50 =(5+2W)\times W\).

Given to us

  • A rectangle’s length is 5 inches more than twice its width.
  • The area of the rectangle is 50 inches².

We will use 'L' to represent the length of the rectangle, while 'W' to represent the Width of the rectangle.

Length of the Rectangle

length is 5 inches more than twice its width, therefore,

\(L = 5+ 2W\)

Area of the rectangle

The area of the rectangle is 50 square inches,

\(\rm{Area = Length \times Width}\)

Substituting the values,

\(50 =L\times W\)

Substituting the value of L,

\(50 =(5+2W)\times W\)

Hence, the equation that can be used to find the width of the rectangle is \(50 =(5+2W)\times W\).

Learn more about Area of Rectangle:

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