shanepierce shanepierce

13-03-2017
Mathematics

Answered

Algebra II Help??? Subtracting Fractions

(2x)/(y^2-x^2) - (x)/(y-x)

Verified Answer :

apologiabiology apologiabiology

13-03-2017

make bottom number same

ok, so remember
(a-b)(a+b)=a²+b²
so

to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)

so multiply 2nd fraction by (y+x)/(y+x)
\(\frac{2x}{y^2-x^2}- \frac{(y+x)(x)}{y^2-x^2}\)=
\(\frac{2x-x(x+y)}{y^2-x^2}\)=
\(\frac{2x-x^2-xy}{y^2-x^2}\)

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