What is the solution to the proportion 3y-8/12=y/5? can someone help me do this?
\(\displaystyle\\
\frac{3y-8}{12} = \frac{y}{5} \\ \\
5(3y-8)=12y\\\\
15y-40=12y\\\\
3y = 40\\\\
\boxed{y = \frac{40}{3}}\)
Answer:
The solution to the proportion \(\frac{3y-8}{12}=\frac{y}{5}\) is \(y=\frac{40}{3}\)
Step-by-step explanation:
Given proportion \(\frac{3y-8}{12}=\frac{y}{5}\)
WE have to find the solution for the given proportion.
Consider the given proportion \(\frac{3y-8}{12}=\frac{y}{5}\).
Cross multiply the terms, we get,
5 (3y - 8) = 12( y )
Simply the terms by multiplying 5 by each term in brackets, we get,
15y - 40 = 12y
taking y terms one sides, we get,
15y - 12y = 40
On simplifying , we get,
3y = 40
Divide both side by 3, we have,
\(y=\frac{40}{3}\)
Thus, the solution to the proportion \(\frac{3y-8}{12}=\frac{y}{5}\) is \(y=\frac{40}{3}\)