A force of 11 N is applied to the handle of a screwdriver being used to pry off the lid of a paint can. As the input force moves through a distance 0.3 m, the screwdriver does 3 J of work on the lid. What is the efficiency of the screwdriver? Show your work

Verified Answer :

joules =mass over a distance
11N0.3m=3.3 Joules
efficiency= energy out/energy in
100%
energy out =energy of the tool=3 J
Energy in = added energy (man)=3.3 J
3/3.3*100%=90.91%

Answer : The efficiency of the screwdriver is \(90.91\%\)

Explanation :

Applied force on the handle of screwdriver, F = 11 N

Distance covered by the input force, d = 0.3 m

Output work, \(W_o=3\ J\)

Efficiency of the screwdriver is given by the following relation :

\(E=\dfrac{W_o}{W_i}\times 100\)

\(E=\dfrac{3\ J}{11\ N\times 0.3\ m}\times 100\)

\(E=90.91\%\)

Hence, this is the required solution.