A force of 11 N is applied to the handle of a screwdriver being used to pry off the lid of a paint can. As the input force moves through a distance 0.3 m, the screwdriver does 3 J of work on the lid. What is the efficiency of the screwdriver? Show your work
joules =mass over a distance
11N0.3m=3.3 Joules
efficiency= energy out/energy in 100%
energy out =energy of the tool=3 J
Energy in = added energy (man)=3.3 J
3/3.3*100%=90.91%
Answer : The efficiency of the screwdriver is \(90.91\%\)
Explanation :
Applied force on the handle of screwdriver, F = 11 N
Distance covered by the input force, d = 0.3 m
Output work, \(W_o=3\ J\)
Efficiency of the screwdriver is given by the following relation :
\(E=\dfrac{W_o}{W_i}\times 100\)
\(E=\dfrac{3\ J}{11\ N\times 0.3\ m}\times 100\)
\(E=90.91\%\)
Hence, this is the required solution.