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aaz aaz
  • 19-02-2015
  • Mathematics
Answered

if t is a number greater than 1, then t^2 is how ,much greater than t?

Verified Answer :

Anonymous Anonymous
  • 19-02-2015

\(t^{2} -1 >0\)
Therefore, \(t(t-1)>0\)

Answer: \(t(t-1)\)

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