sinΘ = 15/17 and Θ lies in Q1, find cos 2Θ
\(\cos^2\theta=1-\sin^2\theta\)\(\cos^2\theta=1-\dfrac{225}{289}=\dfrac{64}{289}\)\(\cos2\theta=\cos^2\theta-\sin^2\theta\)\(\cos2\theta=\dfrac{64}{289}-\dfrac{225}{289}=-\dfrac{161}{289}\)
