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Answer:

The measure of the angle opposite the leg that is 6 inches long is

\(30^{\circ}\)

Step-by-step explanation:

We have been given sides of right triangle that is we will use pythagoras theorem:

\(hypotenuse^2=side^2+side^2\)

Here, we have one side which is 6 inches

And other side is \(6\sqrt{3}\) inches on substituting the values in the formula above we get:

\(hypotenuse^2=6^2+(6\sqrt{3})^2\)

\(hypotenuse^2=36+108\)

\(\Rightarrow hypotenuse^2=144\)

\(\Rightarrow hypotenuse=12\)

The angle will be \(sin\theta=\frac{perpendicular}{hypotenuse}\)

\(sin\theta=\frac{6}{12}\)

\(\Rightarrow sin\theta=\frac{1}{2}\)

\(\Rightarrow \theta=sin^{-1}(\frac{1}{2})\)

\(\Rightarrow \theta=30^{\circ}\)

Hence,  the measure of the angle opposite the leg that is 6 inches long is

\(30^{\circ}\)

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The measure of the angle opposite the leg that is 6 inches long is 30°.

What is Tangent (Tanθ)?

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,

\(\rm{Tangent(\theta) = \dfrac{Perpendicular}{Base}\)

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The base is the adjacent smaller side of the angle θ.

Given to us

  • Length of one leg, AB = 6 inches
  • Length of the other leg, BC = 6√3 inches,

The angle opposite to the side of length 6 inches is ∠C,

\(\rm{Tangent(\theta) = \dfrac{Perpendicular}{Base}\)

\(\rm{Tan(\angle C) = \dfrac{AB}{BC}\\\)

\(Tan(\angle C) = \dfrac{6}{6\sqrt3}\\\\Tan(\angle C) = \dfrac{1}{\sqrt3}\\\\(\angle C) = Tan^{-1}\ \dfrac{1}{\sqrt3}\\\\(\angle C)= 30^o\)

Hence, the measure of the angle opposite the leg that is 6 inches long is 30°.

Learn more about Tangent (Tanθ):

https://brainly.com/question/10623976

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