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A 1-kg chunk of putty moving at 1 m/s collides with and sticks to a 5-kg bowling ball initially at rest. The bowling ball and putty then move with a momentum of

A0 kg m/s.
B1 kg m/s.
C2 kg m/s.
D5 kg m/s.
Emore than 5 kg m/s.

Verified Answer :

Momentum P is conserved because there are no external forces acting on the system.

P before = P after = m₁ v₁ + m₂ v₂  

m₁ = 1
m₂ = 5

before:
v₁ = 1
v₂ = 0

Pᵇ = 1·1 + 5 · 0

after:
v₁ = v₂

Pᵃ = Pᵇ

obasola1

Answer:

B) 1 kg m/s.

Explanation:

A 1-kg chunk of putty moving at 1 m/s collides with and sticks to a 5-kg bowling ball initially at rest. The bowling ball and putty then move with a momentum of

A) 0 kg m/s.

B) 1 kg m/s.

C) 2 kg m/s.

D) 5 kg m/s.

E) more than 5 kg m/s.

From the principle of momentum which states that, in a system of colliding bodies, the total momentum before collision must be equal to the total momentum after collision.

m1u1+m2u2=(m1+m2)V

since the collision is inelastic

11+50=momentum after collision

1kgm/s =momentum after the impact

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