Answer:
x= 1, 2
Step-by-step explanation:
The quadratic formula is \(x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\). Here a=1, b=-3, and c=2.
Substitute and you'll have:
\(x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{3+/-\sqrt{(-3)^2-4(1)(2)} }{2(1)}=\frac{3+/-\sqrt{9-8} }{2)}\)
\(\frac{3+/-\sqrt{1} }{2}=\frac{3+/-\sqrt{1} }{2}=\frac{3+/-1 }{2}= 2 , 1\)
