You want to make sure to factor each equation as much as you can first.
So just focus on the numerator first. \(x^3-6x^2+8x\)
To factor the numerator:
\((x)(x^2-6x+8)\) factor out an x
\((x)(x-4)(x-2)\) factor out the rest completely.
Now for the denominator: \(-4x^2+4x+24\)
\((-4)(x^2+x+6)\) factor out a -4
\((-4)(x+3)(x-2)\) factor out the rest.
This leaves you with:
\(\frac{(x)(x-4)(x-2)}{(-4)(x+3)(x-2)}\)
Then you can simplify:
\(\frac{(x)(x-4)}{(-4)(x+3)}\)
I'm not sure what you're supposed to find exactly, so if you need more help you can ask me (:
