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Verified Answer :

We have to find the value of the expression \(i^{233}\)

We know that the below values.

\(i^2=-1\\i^4=1\)

Hence, in order to find the value of the given expression, we can first rewrite it in terms of \(i^4\)

\(i^{233}=(i^4)^{58}\cdot i\)

Now, we know that \(i^4=1\)

Hence, we have

\(i^{233}=(1)^{58}\cdot i\)

\(i^{233}=1\cdot i\)

\(i^{233}=i\)

C is the correct option.

The value of \(i ^{233}\) is \(i\).

Given to us

  • \(i ^{233}\)

What is the value of  \(i ^{233}\)?

We know the value of iota(i ) is equal to √-1.

therefore, the expression can be written as,

\(i^{233} = (\sqrt{-1})^{233}\)

It can be furthered written as,

\(i^{233} = (\sqrt{-1})^{233}\\\\\),

Using the exponential rule \(x^a \times x^b = x^{(a+b)}\)

\(i^{233} = (\sqrt{-1})^{232} \times (\sqrt{-1})\\\\\)

Using \((x^a)^b =x^{ab}\),

\(i^{233} = [(\sqrt{-1})^2]^{116} \times (\sqrt{-1})\\\\i^{233} = (-1})^{116} \times (\sqrt{-1})\\\\i^{233} = 1 \times (\sqrt{-1})\\\\i^{233} = 1 \times i\\i^{233} = i\)

Hence, the value of \(i ^{233}\) is \(i\).

Learn more about the Exponential rule:

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