Answer:
Option A is correct
Vertex = (2, -7)
Step-by-step explanation:
A quadratic equation is in the form of:
\(ax^2+bx+c=0\) .....[1]
then;
Axis of symmetry is given by:
\(x =\frac{-b}{2a}\)
Vertex = \((\frac{-b}{2a}, f(\frac{-b}{2a})\)
As per the statement:
The equation :
\(f(x) = 4^2- 16x + 9\)
On comparing with [1] we have;
a = 4, b = -16 and c =9
we have;
\(x = \frac{-(-16)}{2 \cdot 4} = \frac{16}{8} = 2\)
Substitute x= 2 in f(x) we have;
\(f(2) = 4(2)^2-16(2)+9 = 16 - 32+9 = -16+9 = -7\)
Vertex = (2, -7)
therefore, the vertex of the parabola is, (2, -7)
