9^3x-7=9^5-x what is the answer
we can take the 9's out and get3x-7=5-x4x=12x=3
ok, so if \(a^m=a^n\) where a=a, then assume that m=nso\(9^{3x-7}=9^{5-x}\), 9=9, so 3x-7=5-x3x-7=5-xadd x to both sides4x-7=5add 7 to both sides4x=12divide both sides by 4x=3
