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The equation h(t)=−16t2+120t+65 gives the height of a firework, in feet, t seconds after it is launched from a platform.


What is the height of the platform?


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ft

Verified Answer :

h(0)=-16(0)^2+120(0)+65
h(0)=65
65 feet

Answer:

The  height of the platform is 65 ft

Step-by-step explanation:

Given :  The equation \(h(t)=-16t^2+120t+65\) gives the height of a firework, in feet, t seconds after it is launched from a platform.

We have to find the height of the platform.

Since the firework is launched from the platform so the initial height of firework will give the height of the platform.

So, the firework is at platform when t = 0 in the given equation   \(h(t)=-16t^2+120t+65\)  

At t = 0

\(h(0)=-16(0)^2+120(0)+65\)  

Simplify , we have,

\(h(0)=65\)

Thus, The  height of the platform is 65 ft

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