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Verified Answer :

sector area = (Central Angle (Degrees) / 360) PI radius^2
One way to solve this is that an angle of (PI/4) = 45 degrees.
45 degrees is one eighth of a circle.
Area of ENTIRE circle = PIradius^2 = PI 3^2 =



28.2743338823



square centimeters
Area of the sector is one eighth of this =



3.5342917353




square centimeters

Answer:

Let l be the length of an ac and r be the radius of the circle.

Use the fact that the length of an arc intercepted by an angle is proportional to the radius

i.e

\(l \propto r\)

⇒\(l = r \theta\) where, \(\theta\) is the angle in radian.

To find the Area of the sector:

Given: r = 3 cm and \(\theta = \frac{\pi}{4}\)

\(\text{Area of the sector A} = \pi r^2 \cdot \frac{\theta}{360^{\circ}}\)

where, \(\theta\) is the angle in degree.

Use conversion:

1 radian = \(\frac{180}{\pi}\) degree

then;

\(\frac{\pi}{4}\) = \(\frac{\pi}{4 } \times \frac{180}{\pi} = 45^{\circ}\)

then;

\(\theta =45^{\circ}\) and use \(\pi = 3.14\)

Substitute the given values we have;

\(A= 3.14 \cdot 3^2 \cdot \frac{45}{360}\)

⇒\(A = 3.14 \cdot 9 \cdot 0.125\)

Simplify:

\(A = 3.5325\) square cm

Therefore, the area of the sector is, 3.5325 square cm