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apologiabiology

so it is going right and it has vertex of (-2,1)
so p is positve and h=-2, k=1

(y-k)²=4p(x-h)
(y-1)²=4p(x+2)
well, eliminate the ones that have theh x term squared (eliminate B and D)
eliminate the one that is y+1 (A)
answer is C

The required equation of a parabola is \(x =(y-1)^2+2\) . Option c is correct.

A graph of the parabola is given, with vertex (-2, 1). The equation of the parabola is to be determined.

What is a parabola?

A parabola is a cross-section of the cone and is represented by an equation \(y = 4ax^2\).

Here, from the graph axis of the parabola is y = 1.
Now,
equation of a parabola is given by
\(x-h=4(y-k)^2\)
Since (h,k) = (-2,1)
\(x+2=4(y-1)^2\\x = 4(y-1)^2-2\)

Thus, The required equation of a parabola is \(x =(y-1)^2+2\) .

Learn more about parabola here:

brainly.com/question/4074088

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