Answer:
Distance between the poles AB and ED is 15.59 feet .
Step-by-step explanation:
By using the pythagoras theorem
Hypotenuse² = Perpendicular² + Base²
As in ΔABC
AC² = AB² + BC²
AC = 13 ft
AB = 11 ft
Put in the above
13² = 11² + BC²
169 = 121 + BC²
169 - 121 = BC²
48 = BC²
\(BC = \sqrt{48}\)
BC = 6.93 units (Approx)
As in ΔCDE
CE² = CD² + DE²
CE = 10 ft
DE = 5 ft
Put in the above
10² = CD² + 5²
100 = CD² + 25
100 - 25 = CD²
\(CD = \sqrt{75}\)
CD = 8.66 ft (Approx)
Thus
Distance between the poles AB and ED = BC + CD
= 6.93 + 8.66
= 15.59 feet
Therefore the distance between the poles AB and ED is 15.59 feet .
