evarocks352
Answered

Two functions, A and B, are described as follows:


Function A

y = 8x + 3


Function B

The rate of change is 1 and the y-intercept is 4.


How much more is the rate of change of function A than the rate of change of function B?


1

7

8

9

Verified Answer :

calculista

Answer:

\(7\)

Step-by-step explanation:

we have

\(y=8x+3\) -------> equation A

In the equation A the rate of change is equal to the slope m

\(m=8\)

In the equation B

we have

\(m=1\) ------> rate of change

\(b=4\)

The equation B is equal to

\(y=mx+b\)

substitute

\(y=x+4\)

Find the difference of the rate of change of function A minus the rate of change of function B

\(8-1=7\)

Answer:

7

Step-by-step explanation:

The standard model equation here is

y = mx+b

Now,

x and y are the variables

b is y-intercept, it means it is the value of y-coordinate on y axis where this line intercepts on y-axis

m = slope or rate of change or angle ∅ this line making with x -axis.

now arrange function A according to standard model equation

y = (8)x + 3

now, by comparison of standard and function A

m(A) = 8 and b(A) = 3

For function B

it is given that rate of change or slope is 1 and y-intercept is 4

so for function b

m(B) = 1 and b(B) = 4

Now question is about how much slope of function A is more than slope of function B

m(A)-m(B) = 8-1 = 7

So answer is 7.

Related Questions