if we take it that, the total amount is say hmmm "x"
then one can say that \(\bf \begin{cases}
\cfrac{2}{5}x\impliedby &\textit{no horns}\\\\
\cfrac{1}{7}x\impliedby &\textit{one horn}\\\\
\cfrac{1}{3}x\impliedby &\textit{two horns}\\\\
26\impliedby &remaining
\end{cases}
\\\\\\
\textit{so the total is really }\quad \cfrac{2}{5}x+\cfrac{1}{7}x+\cfrac{1}{3}x+26\)
add up the fractions of "x" and the constant of 26
