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Answered

Question 10

A 75.0 −mL sample of 1.54×10−2 M Na2SO4(aq) is added to 75.0 mL of 1.22×10−2 M Ca(NO3)2(aq).

Part A

What percentage of the Ca2+ remains unprecipitated?

Express your answer using two significant figures.

Verified Answer :

taskmasters

the reaction that should be followed is
Na2SO4 + Ca(NO3)2 --> CaSO4 + 2NaNO3
first calculate the limiting reactant
mol Na2SO4 = 0.075 L (1.54×10−2 mol / L) = 1.155x10-3 mol


mol Ca(NO3)2 = 0.075 L (1.22×10−2 mol / L) = 9.15x10-4 mol
so the limiting reactant is the Ca(NO3)2

so all of the Ca2+ will be precipitated, percentage unprecipitated = 0.00 %