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rarrininger

A= B + Bcd

A-B= B - B +Bcd

A-B = Bcd

A-B/B = Bcd/B

A-1=cd/d


A-1/d =c


c=A-1/d

Answer

Given that: \(A = B+Bcd\)

The distributive property says that:

\(a \cdot(b+c) = a\cdot b+ a\cdot c\)

Then;

Apply distributive property to the given equation:

\(A = B(1+cd)\)

Divide both sides by B we get;

\(\frac{A}{B} = 1+cd\)

Subtract 1 from both sides we get;

\(\frac{A}{B}-1 = cd\)

Simplify:

\(\frac{A-B}{B} = cd\)

Divide both sides by d we get;

\(\frac{A-B}{Bd} = c\)

Therefore, the formula for c is :

\(c=\frac{A-B}{Bd}\)


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