Advance tickets for a school play went on sale. The price of each student ticket was $4 and everyone else paid $5. On the first day, no more than $80 in tickets were sold. Describe and explain the possible values of s, the number of student tickets sold, and e, the number of tickets sold to nonstudents.

Sample Answer: Partial and negative tickets cannot be sold, so the minimum number values of e and s are 0. If s = 0, then e = 16, and if e = 0, then s = 20. Therefore, the values of s are whole numbers from 0 to 20 and the values of e are whole numbers between 0 and 16. The greatest number of student tickets sold was 20 and the greatest number of non-student tickets sold was 16.

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nishantwork777 nishantwork777 · Answer 2 · 2021-10-19T02:45:31-04:00

The possible values of students tickets and other tickets are:

$s=(0 \;\text{to}\; 20) \;\text{and} \;\\e=(0 \;\text{to}\;16)$

Step-by-step explanation:

Given information:

The price of each student tickets was $4

The price for everyone else was $5

The number of tickets sold for students is $s$

And $e$ for everyone else:

Hence , the maximum possible value for students tickets when everyone else is zero

Hence, $s=20$ and $e=0$

Similarly, for,

$s=0$ the value of $e=16$

Hence , the possible values of students tickets and other tickets are:

$s=(0 \;\text{to}\; 20) \;\text{and} \;\\e=(0 \;\text{to}\;16)$

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