Answer:
\(\:\:\left(6q+7\right)\left(2q+3\right)=12q^2+32q+21\)
Table is shown below
Step-by-step explanation:
Given expression \(\:\:\left(6q+7\right)\left(2q+3\right)\)
We have to find the product of given expression using table.
Consider the given expression \(\:\:\left(6q+7\right)\left(2q+3\right)\)
We have to find the product of given expression \(\:\:\left(6q+7\right)\left(2q+3\right)\)
Apply FOIL METHOD,
Multiply Each term in first bracket with each term in second bracket,
\(\left(a+b\right)\left(c+d\right)=ac+ad+bc+bd\)
We have,
\(=6q\cdot \:2q+6q\cdot \:3+7\cdot \:2q+7\cdot \:3\)
Simplify, we have,
\(=6\cdot \:2qq+6\cdot \:3q+7\cdot \:2q+7\cdot \:3\)
Simplify, we have,
\(=12q^2+32q+21\)
