Answer:
x=5.196m
Step-by-step explanation:
From the given figure, we have
Consider the triangle ADE, using trigonometry, we have
\(\frac{AD}{ED}=cot30^{\circ}\)
substituting the given values, we have
\(\frac{x}{3}=cot30^{\circ}\)
\(\frac{x}{3}=\sqrt{3}\)
\(x=3\sqrt{3}\)
\(x=3(1.732)\)
\(x=5.196\)
Therefore, the value of the slant height x of the square pyramid is 5.196m.
