Answer:
\(\frac{2}{5}\) is the required probability.
Step-by-step explanation:
The probability P(A or B) when A and B are mutually exclusive events is P(A) + P(B)
Here A is the event hitting a Bull's eye
and B is the event throwing dart into 10 point ring.
The probability that he throws a dart into the center of the dart board (the Bull’s eye) = \(\frac{1}{10}\).
The probability that he throws the dart into the 10-point ring = \(\frac{3}{10}\)
Required probability = \(\frac{1}{10}\)+ \(\frac{3}{10}\) = \(\frac{4}{10}\) = \(\frac{2}{5}\)
