how would you find the x-intercept of f(x)=(x-4)^2-3?
The x -intercepts occur when f(x) =0So,(x-4)^2 = x^2 -8x + 16 -3 =0x^2 -8x + 13 =0Solving by the quadratic formula x1 = 5.7321x2 = 2.2679