Answer:
The vertex of the graph is (-3,2).
Step-by-step explanation:
We are given that an equation
\(y=-4(x+3)^2+2\)
We have to find the vertex of given equation.
General equation of parabola along y- axis with vertex (h,k) is given by
\(y-k=a(x-h)^2\)
\(y=a(x-h)^2+k\)
Compare it with the given equation
Then, we get
\(h=-3, k=2\)
Hence, the vertex of given equation is (-3,2).
