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Verified Answer :

apologiabiology

ok, so remember
\(x^{-m}= \frac{1}{x^m}\)
and \((x^m)(x^n)=x^{m+n}\)

so
\((a^{-2})+(a^{-1})(b)- (\frac{b^2}{a^2}) (b^{-1})\)=
\(( \frac{1}{a^2} )+( \frac{b}{a} )-( \frac{(b^2)(b^{-1})}{a^2} )\)=
\(( \frac{1}{a^2} )+( \frac{b}{a} )-( \frac{b^1}{a^2} )\)
common denomenator
times 2nd fraction by a/a
\(( \frac{1}{a^2} )+( \frac{ab}{a^2} )-( \frac{b^1}{a^2} )\)
add/subtract
\(\frac{1+ab+b}{a^2}\)

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