At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist heading north is riding 6 km/hour faster than the bicyclist heading south. At 10:15, they are 42.5 km apart. Find the two bicyclists’ rates.
Answer:
the speed of the bicyclist heading south 14
the speed of the bicyclist heading north 20
Step-by-step explanation:
Let x is the speed of the bicyclist heading south
Let x+6 is the speed of the bicyclist heading north
Because, they are heading in opposite directions, so the relative speed is:
x + x + 6 = 2x+6
As we know:
\(\dfrac{Distance}{time}=Speed\)
<=> \(\dfrac{42.5}{\dfrac{5}{4}}=2x+6\)
<=> 170 = 10x + 30
<=> x = 14 km/hour
=> Speed of bicyclist heading north would be 14+6=20 km/hr
Hope it will find you well.