Answer: \(5u^2v^2\)
Step-by-step explanation:
Given monomials : \(15u^2v^3, 20u^5v^2, 45u^3v^5\)
We can rewrite the above monomials as product below :-
\(15u^2v^3=5\times3u^2v^3\\\\ 20u^5v^2=5u^5v^2\times4\\\\45u^3v^5=5\times9u^3v^5\)
Therefore, the greatest common factor for numerical coefficients of monomials = 5
Also, the greatest common power of u =2
and the greatest common power of v = 2
Hence, the greatest common factor of \(15u^2v^3, 20u^5v^2, 45u^3v^5\) is \(5u^2v^2\)
