when 2x^2/y = w+2/4 is solved for w, one equation is
when 2x^2/y = w+2/4 is solved for w, one equation is
B, because you can cancel the y in -2y and the answer will still be the same
Hope this helps :)
Answer: w= \(\frac{8x^{2} - 2y }{y}\)
Step-by-step explanation:
From the question above, we have;
\(\frac{2x^{2} }{y} = \frac{w + 2}{4}\)
We will have to make w subject of the formula. To do that we will first have to cross multiply
2x² × 4 = (w +2) y
8x² = (w + 2 ) y
we will now divide both-side of the equation by y
\(\frac{8x^{2} }{y}\) = w + 2
we will then subtract 2 from both-side of the equation
\(\frac{8x^{2} }{y}\) - 2 = w
We shall now make the left hand side of the equation a standard fraction
\(\frac{8x^{2} - 2y}{y}\) = w
Therefore w = \(\frac{8x^{2} - 2y}{y}\)