If your'e looking to complete the square, then here's how you do it:
1.) Subtract 7 from each side: \(x^{2} -8x=-7\)
2.) Take half of the value of B, which is 4, then square it to get C
3.) Now you should have \(x^{2} -8x+(4)^2=-7+(4)^2\), because what you do to one side you have to do to the other
4.) Take the value of \(x^{2}\) and 4, and plug them into an ordered pair: \((x-4)^2=9\)
Now take the square root of both sides which is equal to \(x-4=\)±\(3\)
5.) Now subtract 4 from each side to isolate x: \(x=4\)±3
6.) Solve: \(x=4-3\) & \(x=4+3\)
Final Answer: \(x=1\) & \(x=7\)
Hope this helps!!
