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Verified Answer :

bcalle

A= (1/2) bh
h=3 sqrt3
A= (1/2)
6*3sqrt3
A= 9sqrt3 square inches

Answer:

The area of the triangle is 9√3 in²

Step-by-step explanation:

We know that, the area of an equilateral triangle is,

\(A=\frac{\sqrt{3}}{4}a^2\)

Where, a is the side of the triangle,

Given,

a = 6 inches,

Thus, the area of the given equilateral triangle is,

\(A=\frac{\sqrt{3}}{4}(6)^2\)

\(=\frac{36\sqrt{3}}{4}\)

\(=9\sqrt{3}\text{ square inches}\)