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Allen's team was also required to buy two pairs of uniform pants and two baseball caps, which total $68. A pair of pants cost $12 more than a baseball cap.

Verified Answer :

roguejedi1123

Variables:
p = uniform pants
c = baseball caps

Equations:
\(2p + 2c = 68\)
\(p - c = 12\)
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Step 1.
\(\left {{2p+2c=68} \atop {p-c=12}} \right\)

Step 2.
\(\left {{2p+2c=68} \atop {2(p-c=12)}} \right.\)

Step 3.
\(\left {{2p+2c=68} \atop {2p-2c=24}} \right.\)

Step 4.
\(4p = 92\)

Step 5.
\(\frac{4p}{4} = \frac{92}{4}\)
\(p=23\)

Step 6.
\(p-c=12\)
\(23 - c=12\)
\(23=12+c\)
\(11=c\)

Baseball Pants = $23
Baseball Caps = $11

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