Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)
Formula:
\(M = \frac{m}{MM*V}\)
Solving:
\(M = \frac{m}{MM*V}\)
\(1.75 = \frac{35}{58.44*V}\)
\(1.75*58.44V = 35\)
\(102.27V = 35\)
\(V = \frac{35}{102.27}\)
\(\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark\)
