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A large blue marble of mass 3.5 g is moving to the right with a velocity of 15 cm/s. The large marble hits a small red marble of mass 1.2 g that is moving to the right with a velocity of 3.5 cm/s. After the collision, the blue marble moves to the right with a velocity of 5.5 cm/s.


What is the magnitude of the final velocity of the red marble?


9.2 cm/s

14 cm/s

24 cm/s

31 cm/s

Verified Answer :

skyluke89

Answer:

31 cm/s

Explanation:

Let's solve the problem by using conservation of momentum:

\(m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\)

where:

\(m_1 = 3.5 g\) is the mass of the blue marble

\(m_2=1.2 g\) is the mass of the red marble

\(u_1 = 15 cm/s\) is the initial velocity of the blue marble

\(u_2 = 3.5 cm/s\) is the initial velocity of the red marble

\(v_1 = 5.5 cm/s\) is the final velocity of the blue marble

We can find the final velocity of the red marble by re-arranging the equation and solving for \(v_2\):

\(v_2 = \frac{1}{m_2}(m_1 u_1 + m_2 u_2 - m_1 v_1)=\)

\(=\frac{1}{1.2}(3.5\cdot 15 + 1.2 \cdot 3.5 - 3.5 \cdot 5.5  )=31 cm/s\)

Answer:

31

Explanation:

edge 2021

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